Posted by **Jordan** on Monday, January 9, 2012 at 4:32pm.

A circular pulley with a radius of 10 cm is turning at 12 revolutions per minute. How

fast is a point on the edge of the pulley rising when it is 5 cm higher than the center of

the pulley?

- Help Math -
**Steve**, Monday, January 9, 2012 at 4:57pm
Draw a diagram. Consider point P on the circle, at height h above the center of the pulley. Let the radius from the center to P make angle θ with the horizontal.

h/r = sinθ

since r = 10,

h = 10 sinθ

dh/dt = 10 cosθ dθ/dt

Since the wheel is turning at 12 rpm, dθ/dt = 24π/min

dh/dt = 10 * √3/2cm * 24π/min = 653 cm/min

- Help Math -
**Jordan**, Monday, January 9, 2012 at 5:00pm
Thanks Steve

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