Wednesday

March 4, 2015

March 4, 2015

Posted by **Shreya** on Monday, January 9, 2012 at 10:13am.

5y/(2y-3)(3y+1)+(4y-3)(2y-3)(y-6)

i not get what it asking for.

- math-calculus -
**Reiny**, Monday, January 9, 2012 at 10:35am5y/( (2y-3)(3y+1) )+(4y-3)/((2y-3)(y-6) )

look at the denominators .

We know we cannot divide by zero, so the "nonpermissible" values of x would be all those that make either one of the denominators zero.

But you factored it, so that is good, all we have to find out which values make any of the factors equal to zero

so.....

2y-3 ≠ 0

2y ≠ 3

y ≠ 3/2

3y+1 ≠ 0

3y ≠ -1

y ≠ -1/3

and

y ≠ 6

so the nonpermissible values of x are -1/3, 2/3 and 6

- math-calculus -
**Shreya**, Monday, January 9, 2012 at 10:48amthanks very much reiny :)

**Answer this Question**

**Related Questions**

Calculus - Simplify. State the nonpermissible values. 4a^2-1/4a^2-16*2-a/2a-1 ...

Calculus - Simplify. State the nonpermissible values. (3t^2+3t-6/2t^2-2t-4)(4t^2...

Pre-Algebra [repost ] - I need help on these three questions BEFORE 10:00 PM. ...

maths - Consider the quadratic equation m^2 x^2 + 2(2m-5)x + 8 = 0 a) If 2 is a ...

math - Evaluate the exponential equation for three positive values of x, three ...

calculus - Consider the function f(x)=x^n for positive integer values of n. (a) ...

Algebra - Totally lost here! Evaluate the exponential equation for three ...

Algebra - Evaluate the exponential equation for three positive values of x, ...

Intermediate Algebra - Evaluate the exponential equation for three positive ...

Intermediate algebra - Evaluate the exponential equation for three positive ...