Homework Help: chemical equilibrium

Posted by Anonymous on Monday, January 9, 2012 at 2:06am.

At a certain temperature, Kc = 0.914 for the reaction

NO2 (g) + NO (g) <----> N2O (g) + O2 (g)

Equal amounts of NO and NO2 are to be placed in a 5.00 L container until the N2O concentration at equilibrium is 0.050 M. How many moles of NO and NO2 must be placed in the container?

chemical equilibrium - Anonymous, Monday, January 9, 2012 at 2:09am
the answer is 0.261 moles
chemical equilibrium - DrBob222, Monday, January 9, 2012 at 1:12pm
..........NO2 + NO ==> N2O + O2
initial....x.....x.....0......0
equil................0.05....0.05

Kc = 0.914 = (N2O)(O2)/(NO2)(NO)
(N2O) = x
(NO) = x
(N2O) = 0.05
(O2) = 0.05
Solve for x which is molarity NO2 and NO.
Then moles = M x L to solve for moles.

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