Math
posted by Brittany snow on .
What is the sum of the first 200 odd numbers?
A rectangle has an area of 120 cm square we are trying to find possible perimeters. It's length and width are whole numbers. What are all the possibilities for the 2 numbers?
Give next two terms
3,4,7,11,18,29....
1,2,6,24,120....
77,49,36,18....

Odd numbers: 1 , 3 , 5...
200th od number = 399
Now:
1 + 399 = 400
3 + 397 = 400
5 + 395 = 400
....
199 + 201 = 400
100 * 400 = 40,000
A = L * W = 120
L = 120 / W
120 = 2 * 2 * 2 * 3 * 5
Ohe possibilities for the 2 numbers all numbers dividable with 2 3 and 5
W = 120 , L = 120 / 120 = 1
W = 60 , L = 2
W = 30 , L = 4
W = 15 , L = 8
W = 10 , L = 12
W = 8 , L = 15
W = 6 , L = 20
W = 4 , L = 30
W = 3 , L = 40
W = 2 , L = 60
W = 1 , L = 120
3,4,7,11,18,29....
The previous two numbers make up the next number:
3 + 4 = 7
7 + 4 = 11
11 + 7 = 18
11 + 18 = 29
Last two are:
18 + 29 = 47
and
29 + 47 = 76
3 ,4 , 7 , 11 , 18 , 29 , 47 , 76
1 , 2 , 6 , 24 , 120..
The multiplier increases by one each time:
1 x 2 = 2
2 x 3 = 6
6 x 4 = 24
24 x 5 = 120
120 x 6 = 720
720 x 7 = 5040
1 , 2 , 6 , 24 , 120 , 720 , 5040
77 , 49 , 36 , 18 ...
77
7 x 7 = 49
4 x 9 = 36)
3 x 6 = 18
1 x 8 = 8)
0 x 8 = 0
77 , 49 , 36 , 18 , 8 , 0