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March 29, 2017

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A pendulum has a period of 0.70 s on Earth. What is its period on a planet where the acceleration of gravity is about 0.31 that on Earth?

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    T1=2π•sqrt(L/g)
    T2=2π•sqrt(L/0.31g)
    T2=T1/sqrt(0.31)=0.7/0.557=1.26 s.

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