Posted by **Shreya** on Sunday, January 8, 2012 at 9:34pm.

15+2y-y^2/3y^2-16y+5

(5-y)(3+y)/(3y-1)(y-5)

i factor out a negative one from (5-y) to make it same like (y-5)

(-1)(-5+y)(3+y)/(3y-1)(y-5)

i cancel off y-5's. and i get

(-1)(3+y)/(3y-1)

but the real answer have to be 3+y/1-3y what i doing wrong?

- math-calculus -
**Reiny**, Sunday, January 8, 2012 at 10:23pm
Did you know that -3/4 = 3/-4 = -(3/4)

they are all the same

so look at your answer, which is correct

-1(3+y)/(3y-1)

= (3+y)/(-1(3y-1))

= (3+y)/(1-3y)

Sometimes it happens that you have an answer that looks different from the one in your text, but you may still be correct.

I would have marked your answer as correct to get full marks.

- math-calculus -
**Shreya**, Sunday, January 8, 2012 at 10:52pm
oh wow i had not know that thanks so much Reiny for telling and explaining to me :)

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