Posted by luckybee on Sunday, January 8, 2012 at 7:45pm.
(x^6)^(1/24) = x^(1/4)
{(x^6)^[(1/2)^3]}^(1/3)
[x^(6/8)]^(1/3)
x^(2/8)
x^1/4
check with x = 2
2^6 = 64
sqrt = 8
sqrt = 2sqrt 2
sqrt = sqrt 2 sqrt (sqrt 2)
= sqrt ( (sqrt2)^3)
now take the cube root of that
[sqrt (2 ^3/2)]^1/3
sqrt (2^1/2) = 2^1/4 sure enough
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