Sunday

March 29, 2015

March 29, 2015

Posted by **luckybee** on Sunday, January 8, 2012 at 7:38pm.

1. the sum of the area of all the circle converge to pi in^2

2. the sum of the areas of all the circles diverge from 2pi in^2

3. the sum of the areas of all the circles converge to 2pi in^2

4. the sum of the areas of all the circles diverge from pi in^2

my solution: i think it is number 4 because the radius ends up being zero.

- math gre question -
**apisit**, Monday, January 9, 2012 at 12:23ama total of 920 adult and student ticket were sold for the school play. the number of student tickets sold was 16 less than twice the number of adult tickets.how many adult tickets were sold?

- math gre question -
**Steve**, Monday, January 9, 2012 at 5:18amsum is pi(1^2 + (1/2)^2 + (1/4)^2 + ...)

= pi (1 + 1/4 + 1/16 + ...)

= pi (1/(1 - 1/4)) = pi (1/(3/4)) = 4pi/3

I think the answer they wanted was 2pi (#3) but 2 = 1 + 1/2 + 1/4 + 1/8 + 1/16 + ...

and we have 1 + 1/4 + 1/16 + 1/64 + ...

a + s = 920

s = 2a-16

a + 2a-16 = 920

3a = 936

a = 312

s = 308 = 2*312 - 16

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