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Trig

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Proving Identities:
2 columns
(tan + cot)^2 = sec^2 + csc^2
I'm having trouble breaking down the left side to = the right side..
Any help please

  • Trig - ,

    left
    (sin/cos + cos/sin)^2

    sin^2/cos^2 + 2 + cos^2/sin^2
    [sin^4 +2sin^2 cos^2+cos^4 ]/cos^2 sin^2
    (sin^2+cos^2)^2/cos^2sin^2
    1^2/sin^2cos^2
    1/sin^2 cos^2

    right
    1/cos^2 + 1/sin^2

    sin ^2/cos^2sin^2 + cos^2/cos^2 sin^2

    1/cos^2 sin^2

  • Trig - ,

    Hi Damon .. apparently they want the right side to stay "as is" and for the left side to transform into exactly what the right side says .... sorry

  • Trig - ,

    I do not think so. That would be a very unusual thing for "them" to say :)

  • Trig - ,

    The question says: Set up a 2 column proof to show that each of the following equations is an identity. Transform the left side to become the right side.
    (tan + cot)^2 = sec^2 + csc^2

  • Trig - ,

    (tan + cot)^2 = tan^2 + 1 + cot^2
    = sec^2 - 1 + 2 + csc^2 - 1
    = sec^2 + csc^2

  • Trig - oops - ,

    oops that's tan^2 + 2 + cot^2

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