Posted by Don on .
Proving Identities:
2 columns
(tan + cot)^2 = sec^2 + csc^2
I'm having trouble breaking down the left side to = the right side..
Any help please

Trig 
Damon,
left
(sin/cos + cos/sin)^2
sin^2/cos^2 + 2 + cos^2/sin^2
[sin^4 +2sin^2 cos^2+cos^4 ]/cos^2 sin^2
(sin^2+cos^2)^2/cos^2sin^2
1^2/sin^2cos^2
1/sin^2 cos^2
right
1/cos^2 + 1/sin^2
sin ^2/cos^2sin^2 + cos^2/cos^2 sin^2
1/cos^2 sin^2 
Trig 
Don,
Hi Damon .. apparently they want the right side to stay "as is" and for the left side to transform into exactly what the right side says .... sorry

Trig 
Damon,
I do not think so. That would be a very unusual thing for "them" to say :)

Trig 
Don,
The question says: Set up a 2 column proof to show that each of the following equations is an identity. Transform the left side to become the right side.
(tan + cot)^2 = sec^2 + csc^2 
Trig 
Steve,
(tan + cot)^2 = tan^2 + 1 + cot^2
= sec^2  1 + 2 + csc^2  1
= sec^2 + csc^2 
Trig  oops 
Steve,
oops that's tan^2 + 2 + cot^2