Posted by Don on Sunday, January 8, 2012 at 7:38pm.
Proving Identities:
2 columns
(tan + cot)^2 = sec^2 + csc^2
I'm having trouble breaking down the left side to = the right side..
Any help please

Trig  Damon, Sunday, January 8, 2012 at 7:49pm
left
(sin/cos + cos/sin)^2
sin^2/cos^2 + 2 + cos^2/sin^2
[sin^4 +2sin^2 cos^2+cos^4 ]/cos^2 sin^2
(sin^2+cos^2)^2/cos^2sin^2
1^2/sin^2cos^2
1/sin^2 cos^2
right
1/cos^2 + 1/sin^2
sin ^2/cos^2sin^2 + cos^2/cos^2 sin^2
1/cos^2 sin^2

Trig  Don, Sunday, January 8, 2012 at 8:21pm
Hi Damon .. apparently they want the right side to stay "as is" and for the left side to transform into exactly what the right side says .... sorry

Trig  Damon, Sunday, January 8, 2012 at 8:40pm
I do not think so. That would be a very unusual thing for "them" to say :)

Trig  Don, Sunday, January 8, 2012 at 8:54pm
The question says: Set up a 2 column proof to show that each of the following equations is an identity. Transform the left side to become the right side.
(tan + cot)^2 = sec^2 + csc^2

Trig  Steve, Monday, January 9, 2012 at 5:10am
(tan + cot)^2 = tan^2 + 1 + cot^2
= sec^2  1 + 2 + csc^2  1
= sec^2 + csc^2

Trig  oops  Steve, Monday, January 9, 2012 at 5:11am
oops that's tan^2 + 2 + cot^2
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