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March 28, 2015

March 28, 2015

Posted by **Belinda** on Sunday, January 8, 2012 at 6:56pm.

1. Solve 2x^3 - 3x^2 = 6x - 9

2. Find all real and imaginary roots of the polynomial equation 3x^4 - x^3 + 4x^2 - 2x - 4=0

3. Find a cubic equation with integral coefficients and roots 3i and -5.

- Cubic Equations -
**Damon**, Sunday, January 8, 2012 at 7:21pm2 x^3 -3 x^2 -6 x + 9 = 0

(2x^3 - 6x) - (3 x^2-9) = 0

2x (x^2-3) -3(x^2-3) = 0

(x^2-3)(2x-3) = 0

you take it from there.

2)

Try x = 1

3-1+4-2-4 = 0 amazing

so divide by (x-1)

(x-1)(3x^3+2x^2+6x+4) = 0

(x-1)[ 3x(x^2+2) + 2(x^2+2) ]

you take it from there

3)

(x+5)(x-3i)(x+3i)

if you have 3i, then you must have the complex conjugate -3i

- Cubic Equations -
**Belinda**, Sunday, January 8, 2012 at 7:22pmThanks so much :D

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