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a hydraulic lift is designed for a gain of 100, so that a 10 N force applied at theinput piston will produce a force of 1,000 N at the output piston. If the radius of the input piston is 2 cm, the radius of the output is

a) 200 cm,
b) .02 cm
c) 400
d) 20
e) .05

  • physics - ,

    area out / area in = 100 = pi Rout^2/ pi Rin^2 = R^2/(2^2)
    R^2 = 400
    R = 20
    so ten times the radius for 100 times the area of course :)

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