Posted by brittney on Sunday, January 8, 2012 at 11:21am.
1. tanAr = -6/-2 = 3.0,
Ar = 71.6 Deg = Reference angle.
A = 180 + Ar = 180 + 71.6 = 251.6 Deg.
Da = 180 - 71.6 = 108.4 Deg.,CCW =
Direction she should aim her canoe.
2. d = V*t,
t = d/V = (2000/5280) / 2 = 0.1894 h =
11.4 min.
The only problem here is that when drawing your reference triangle, the westward speed was 2 and the downstream speed was 6, so you could take the tangent.
When rowing upstream, the 2 mph speed is along the hypotenuse, She can't row the required 2√10 = 6.32 mph needed to end up with a westward speed of 2 mph.
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