Posted by James on Sunday, January 8, 2012 at 10:09am.
P(A ∪ B) = P(A) + P(B) - P(A ∩ B) = 1
I think you'll find that given two possible outcomes, it will always be one or the other. :-)
P(A|B) = P(A ∩ B)/P(B)
Since P(A and B) = 0, P(A|B) = 0
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