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If 0.273 moles of ferrous ammonium sulfate (Fe(NH4)2(SO4)2 . 6H2O) and an excess of all other reagents are used in a synthesis of K2[Fe(C2O4)3] . 3H2O, how many grams of product will be obtained if the reaction gives a 100% yield?
Please help i found the molar mass of (Fe(NH4)2(SO4)2 . 6H2O) = 491.1g/mol and
K2[Fe(C2O4)3] . 3H2O = 392.1 g/ mol.

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