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April 19, 2014

April 19, 2014

Posted by **Shreya** on Saturday, January 7, 2012 at 10:29pm.

(2x-3)(2x+1)-(4x-1) = (0)(x-3)(2x-3)

4x^2+2x-6x-3-4x-1 = 2x^2-3x-6x+9

4x^2-4 = 2x^2-3x-6x+9

-2x^2-9x+13

i put this in quadratic formula and i think it wrong becaue i get 9/2 and 0for x and it have to be 2/3.

- math-calculus -
**Reiny**, Saturday, January 7, 2012 at 11:38pmYour first line should have been

(2x-3)(2x+1)-(4x-1)(x-3) = (0)(x-3)(2x-3)

4x^2 - 4x - 3 - (4x^2 -13x + 3) = 0

4x^2 - 4x - 3 - 4x^2 + 13x - 3 = 0

9x = 6

x = 6/9 = 2/3

- math-calculus -
**Shreya**, Sunday, January 8, 2012 at 4:37pmthank you very much reiny :)

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