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January 26, 2015

January 26, 2015

Posted by **Shreya** on Saturday, January 7, 2012 at 5:38pm.

i be left with

30 = 3x^2-75-2x^2+50

i not sure what to do? i use the quadratic formula?

math-calculus - Steve, Saturday, January 7, 2012 at 3:38pm

First, you have to simplify properly:

30/(x^2-25) = 3/(x-5) - 2/(x+5)

30 = 3(x+5) - 2(x-5)

You were ok multiplying through by x^2 - 25 but you then discarded the denominators on the right, which was incorrect.

3(x^2-25)/(x-5) = 3(x+5)

Anyway, now we are just left with

30 = 3(x+5) - 2(x-5)

which I'm sure you can solve. Just make sure your answer is not 5 or -5, because the original equation is undefined there. The fraction 3/(x-5) is not defined when x=5.

math-calculus - Shreya, Saturday, January 7, 2012 at 5:37pm

thanks Steve but i think im still messing up. i got 30 = x+30

and if i subtract 30 from each side then i only left with x that be no solution. i think i not doing something right.

- math-calculus -
**Damon**, Saturday, January 7, 2012 at 6:28pm30 = 3(x+5) - 2(x-5)

30 = 3 x + 15 - 2x + 10

15 = x + 10

5 = x

THERE IS NO SOLUTION

because 3/(5-5) is division by zero

- math-calculus -
**Shreya**, Saturday, January 7, 2012 at 6:43pmthank you so much damon :)

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