# math-calculus

posted by on .

30/x^2-25 = 3/x-5-2/x+5

i be left with

30 = 3x^2-75-2x^2+50

i not sure what to do? i use the quadratic formula?

math-calculus - Steve, Saturday, January 7, 2012 at 3:38pm
First, you have to simplify properly:

30/(x^2-25) = 3/(x-5) - 2/(x+5)
30 = 3(x+5) - 2(x-5)

You were ok multiplying through by x^2 - 25 but you then discarded the denominators on the right, which was incorrect.

3(x^2-25)/(x-5) = 3(x+5)

Anyway, now we are just left with

30 = 3(x+5) - 2(x-5)

which I'm sure you can solve. Just make sure your answer is not 5 or -5, because the original equation is undefined there. The fraction 3/(x-5) is not defined when x=5.

math-calculus - Shreya, Saturday, January 7, 2012 at 5:37pm
thanks Steve but i think im still messing up. i got 30 = x+30
and if i subtract 30 from each side then i only left with x that be no solution. i think i not doing something right.

• math-calculus - ,

30 = 3(x+5) - 2(x-5)
30 = 3 x + 15 - 2x + 10
15 = x + 10
5 = x
THERE IS NO SOLUTION
because 3/(5-5) is division by zero

• math-calculus - ,

thank you so much damon :)