Sunday

January 25, 2015

January 25, 2015

Posted by **Lee** on Saturday, January 7, 2012 at 5:16pm.

Evaluate

กา dx/3(2x-1)^2

- Calculus -
**Damon**, Saturday, January 7, 2012 at 6:36pm(1/3) integral (2x-1)^-2 dx

let z = 2x-1

then dz = 2 dx

(1/3)(1/2) integral z^-2 dz

(1/6) (-1)z^-1

(-1/6) (2x-1)^-1

-1/[ 6(2x-1) ] + C

**Answer this Question**

**Related Questions**

Calculus Please Help - Evaluate the indefinite integral Note: Use an upper-case...

Calculus - "Evaluate the following indefinite integral using integration by ...

calculus - find the indefinite integral: integration of tan^3(7x) dx

Math - 1. Evaluate the indefinite integral ([6x^2 + 12x^(3/2) +4x+9]/sqrt x)dx. ...

Please help with Calc! - Evaluate the indefinite integral. integral 2e^(2x)sin(e...

Math - Indefinite Integration - Use integration by parts to solve: I = f (x^3)(e...

Calculus - Solve these indefinite and definite integrals. [integration sign] 4j-...

integration (calculus) - Find the indefinite integral. ∫((e^-x-1)/(e^-x + ...

Calc - evaluate the indefinite integral: x^13(cos(x^7))dx I've tried using ...

calculus - evaluate the indefinite integral of ((x+4)/(17+8x+x^2))dx