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March 28, 2015

March 28, 2015

Posted by **Lee** on Saturday, January 7, 2012 at 5:16pm.

Evaluate

กา dx/3(2x-1)^2

- Calculus -
**Damon**, Saturday, January 7, 2012 at 6:36pm(1/3) integral (2x-1)^-2 dx

let z = 2x-1

then dz = 2 dx

(1/3)(1/2) integral z^-2 dz

(1/6) (-1)z^-1

(-1/6) (2x-1)^-1

-1/[ 6(2x-1) ] + C

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