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March 28, 2017

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integration-indefinite

Evaluate
¡Ò dx/3(2x-1)^2

  • Calculus - ,

    (1/3) integral (2x-1)^-2 dx

    let z = 2x-1
    then dz = 2 dx

    (1/3)(1/2) integral z^-2 dz

    (1/6) (-1)z^-1

    (-1/6) (2x-1)^-1

    -1/[ 6(2x-1) ] + C

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