Tuesday

March 31, 2015

March 31, 2015

Posted by **Lee** on Saturday, January 7, 2012 at 4:30pm.

integral sign (x-1/(2x))^2 dx=

- Calculus -
**Steve**, Saturday, January 7, 2012 at 4:35pm(x - 1/(2x))^2 = x^2 - 1 + 1/(4x)

((x-1)/(2x))^2 = (x^2 - 2x + 1)/(4x^2) = 1/4 - 1/(2x) + 1/(4x^2)

Not sure which you meant, but either one is just a sum of terms, which are just powers of x. Just use the normal power rule (or lnx for 1/x) and things are easy.

- Calculus oops -
**Steve**, Saturday, January 7, 2012 at 4:36pmoops. Top one should end with 1/(4x^2)

- Calculus -
**Lee**, Saturday, January 7, 2012 at 5:10pmThanks

**Answer this Question**

**Related Questions**

Calculus II - Evaluate the integral using method of integration by parts: (...

calculus solved - evaluate integral definite integral sign a=1 b=8 4(x^(2/3)+14...

calculus - evaluate the indefinite integral integral sign [8/(x ln(1x))] dx...

calculus - evaluate the indefinite integral integral sign [8/x ln(1x)] dx = +c

Calculus - Evaluate the integral. -2 at the bottom of the integral sign and 7 at...

Math - Find the integrals. (show steps) (integral sign) xe^(4x^2) I think this ...

Calculus - "Evaluate the following indefinite integral using integration by ...

Calculus - Evaluate the integral: 16csc(x) dx from pi/2 to pi (and determine if ...

calculus - the integral sign where 4 is on top and 2 is at the bottom (x/2 + 3)...

Calculus - 1.evaluate (integral sign)x cos 3x dx A.1/6 x^2 sin 3x + C B.1/3 x ...