Posted by Lee on Saturday, January 7, 2012 at 4:30pm.
Evaluate
integral sign (x1/(2x))^2 dx=

Calculus  Steve, Saturday, January 7, 2012 at 4:35pm
(x  1/(2x))^2 = x^2  1 + 1/(4x)
((x1)/(2x))^2 = (x^2  2x + 1)/(4x^2) = 1/4  1/(2x) + 1/(4x^2)
Not sure which you meant, but either one is just a sum of terms, which are just powers of x. Just use the normal power rule (or lnx for 1/x) and things are easy. 
Calculus oops  Steve, Saturday, January 7, 2012 at 4:36pm
oops. Top one should end with 1/(4x^2)

Calculus  Lee, Saturday, January 7, 2012 at 5:10pm
Thanks