Posted by **Lee** on Saturday, January 7, 2012 at 4:30pm.

Evaluate

integral sign (x-1/(2x))^2 dx=

- Calculus -
**Steve**, Saturday, January 7, 2012 at 4:35pm
(x - 1/(2x))^2 = x^2 - 1 + 1/(4x)

((x-1)/(2x))^2 = (x^2 - 2x + 1)/(4x^2) = 1/4 - 1/(2x) + 1/(4x^2)

Not sure which you meant, but either one is just a sum of terms, which are just powers of x. Just use the normal power rule (or lnx for 1/x) and things are easy.

- Calculus oops -
**Steve**, Saturday, January 7, 2012 at 4:36pm
oops. Top one should end with 1/(4x^2)

- Calculus -
**Lee**, Saturday, January 7, 2012 at 5:10pm
Thanks

## Answer This Question

## Related Questions

- calculus (please with steps and explanations) - consider the function f that is ...
- Calculus (urgent help) - consider the function f that is continuous on the ...
- calculus - consider the function f that is continuous on the interval [-5,5] and...
- Calculus II - Evaluate the integral using method of integration by parts: (...
- calculus solved - evaluate integral definite integral sign a=1 b=8 4(x^(2/3)+14...
- Calculus - Evaluate the integral. Problem#1 Integral sign 4dx/[(x+3)(x^2 +3x) ...
- calculus - evaluate the indefinite integral integral sign [8/(x ln(1x))] dx...
- calculus - evaluate the indefinite integral integral sign [8/x ln(1x)] dx = +c
- Calculus - Evaluate the integral. -2 at the bottom of the integral sign and 7 at...
- Math - Find the integrals. (show steps) (integral sign) xe^(4x^2) I think this ...

More Related Questions