Posted by **Lee** on Saturday, January 7, 2012 at 4:30pm.

Evaluate

integral sign (x-1/(2x))^2 dx=

- Calculus -
**Steve**, Saturday, January 7, 2012 at 4:35pm
(x - 1/(2x))^2 = x^2 - 1 + 1/(4x)

((x-1)/(2x))^2 = (x^2 - 2x + 1)/(4x^2) = 1/4 - 1/(2x) + 1/(4x^2)

Not sure which you meant, but either one is just a sum of terms, which are just powers of x. Just use the normal power rule (or lnx for 1/x) and things are easy.

- Calculus oops -
**Steve**, Saturday, January 7, 2012 at 4:36pm
oops. Top one should end with 1/(4x^2)

- Calculus -
**Lee**, Saturday, January 7, 2012 at 5:10pm
Thanks

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