30/x^2-25 = 3/x-5-2/x+5
i be left with
30 = 3x^2-75-2x^2+50
i not sure what to do? i use the quadratic formula?
First, you have to simplify properly:
30/(x^2-25) = 3/(x-5) - 2/(x+5)
30 = 3(x+5) - 2(x-5)
You were ok multiplying through by x^2 - 25 but you then discarded the denominators on the right, which was incorrect.
3(x^2-25)/(x-5) = 3(x+5)
Anyway, now we are just left with
30 = 3(x+5) - 2(x-5)
which I'm sure you can solve. Just make sure your answer is not 5 or -5, because the original equation is undefined there. The fraction 3/(x-5) is not defined when x=5.
thanks Steve but i think im still messing up. i got 30 = x+30
and if i subtract 30 from each side then i only left with x that be no solution. i think i not doing something right.
To solve the equation 30/x^2-25 = 3/x-5-2/x+5, you need to simplify and rearrange the equation to a form that can be solved easily. Let's go through the steps:
1. Start by multiplying both sides of the equation by (x^2 - 25) to eliminate the denominators:
30 = 3(x + 5) - 2(x - 5)
2. Expand and simplify both sides:
30 = 3x + 15 - 2x + 10
30 = x + 25
3. Now, isolate the variable x by subtracting 25 from both sides:
x = 30 - 25
x = 5
So, the solution to the equation is x = 5.
You don't need to use the quadratic formula in this case because the equation simplifies to a linear equation after eliminating the denominators.