Posted by Jason on Friday, January 6, 2012 at 9:23pm.
The kinetic energy of the bullet and block after impact equals the work done against friction.
(1/2)(M+m)V2^2 = (M+m)*g*(0.7)*14m
V2^2 = 2*g*(0.7)(14) = 192 m^2/s^2
V2 = 13.9 m/s
Now use conservation of momentum to determine the velocity of the bullet, V1
m*V1 = (m+M)*V2
V1 = V2*(121/11) = 11 V2 = 152 m/s
Related Questions
physics - A(n) 11 g bullet is fired into a(n) 111 g block of wood at ...
Physics - A(n) 15 g bullet is fired into a(n) 116 g block of wood at ...
physics - A 14 g bullet is fired into a 120 g wooden block initially ...
physics - A 25 g bullet is fired from a gun into a 1.35 kg block of wood ...
Physics - A 15.0 gram bullet strikes and becomes embedded in a 1.24 kg block of ...
University Physics - A 8.3-g bullet, when fired from a gun into a 1.1-kg block ...
physics - A 11.0 g bullet is fired horizontally into a 108 g wooden block that ...
physics - a 100-g bullet is fired horizontally into a 14.9kg block of wood ...
physics - A rifle fires a(n) 3 g bullet with a muzzle ...
Physics - A 50g bullet strikes a stationary 1.50kg block of wood paced on a ...
For Further Reading