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September 17, 2014

September 17, 2014

Posted by **sai** on Friday, January 6, 2012 at 1:03pm.

anxiety in a sample of college students. A standard measure of test anxiety is known to

produce a = 19. In the sample you draw of 86 the mean is equal 17.5 with standard

deviation s = 10.

a- Use an level of 0.05 to test the hypothesis that the mean is less than 19.

b- Find the 95 % one sample con dence interval for the mean.

- statistics -
**PsyDAG**, Sunday, January 8, 2012 at 12:59pmZ = (mean1 - mean2)/standard error (SE) of difference between means

SEdiff = √(SEmean1^2 + SEmean2^2)

SEm = SD/√n

If only one SD is provided, you can use just that to determine SEdiff.

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion related to the Z score. Remember that your hypothesis leads to a one-tailed test.

95% = mean ± 1.96 SEm

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