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November 20, 2014

November 20, 2014

Posted by **Izzy.** on Thursday, January 5, 2012 at 10:06pm.

- Math, I NEED HELP.c: -
**Izzy.**, Thursday, January 5, 2012 at 10:29pmD:

- Math, I NEED HELP.c: -
**Reiny**, Friday, January 6, 2012 at 9:06amequation:

cost = yt + x, where t is the number of hours

case1:

4y + x = 63 ---> x = 63-4y

case2:

6y + x = 87 ---> x = 87-6y

so 63-4y = 87-6y

2y = 24

y = 12

back into 1st equation:

x = 63-4(12) = 15

cost equation:

cost = 12t + 15

so for 11 hrs

cost = 12(11)+15

= 147

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