A copy center offers its customers two different pricing plans for black and white photocopies of 8.5 in. by 11 in. pages. Customers can either pay $0.08 per page or pay $7.50 for a discount card that lowers the cost to $0.05 per page. Which equation can be used to solve for the number of photocopies for which the cost of each plan is the same?
hannah wants to buy a $750 camera. she can save $50 each week from her paycheck. however, before hannah can buy the camera< she must give her brother $80 that she owes him. for how many weeks will hannah need to save before she can pay back her brother and buy the camera
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ISHDIS
To solve for the number of photocopies for which the cost of each plan is the same, we can start by setting up an equation.
Let x be the number of photocopies.
For the first pricing plan, the cost per page is $0.08, so the total cost for x photocopies would be 0.08x.
For the second pricing plan, the cost per page is $0.05, but there is an additional cost of $7.50 for the discount card. So the total cost for x photocopies would be 0.05x + $7.50.
Now we can set up the equation:
0.08x = 0.05x + $7.50
To solve for x, we can start by subtracting 0.05x from both sides of the equation:
0.08x - 0.05x = $7.50
0.03x = $7.50
Finally, we divide both sides by 0.03 to isolate x:
x = $7.50 / 0.03
x ≈ 250
So, the equation that can be used to solve for the number of photocopies for which the cost of each plan is the same is:
0.08x = 0.05x + $7.50
for n copies,
cost of plan1 = .08n
cost of plan2 = 7.5 + .05n
when is .08n = 7.5 = .05n
multiply by 100
8n = 750 + 5n
3n = 750
n = 250