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October 30, 2014

October 30, 2014

Posted by **Mishaka** on Thursday, January 5, 2012 at 6:00pm.

- Calculus ~ Related Rates -
**Reiny**, Thursday, January 5, 2012 at 6:52pmFrom what you said, I will assume you defined variables as such....

x is the distance between the man and the streetligh

y is the length of his shadow.

then dx/dt = -2 , find dy/dt

by similar triangles:

2/y = 5/(x+y)

5y = 2x + 2y

3y = 2x

3dy/dt = 2dxdt

dy/dt = 2(-2)/3 = -4/3

so his shadow is decreasing at a rate of 4/3 m/s

(notice , since I said "decreasing", I do not use the negative sign, since the word decreasing implies it)

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