x intercepts of f(x)15x^2-12x-48
It should probably read
f(x) = 15x^2 - 12x - 48
for x-intercepts, let f(x) or y = 0
15x^2 - 12x - 48 = 0
hint: divide each term by 3, then use the quadratic formula.
Get back to me with your answer.
I got 4+-sqr(336) / 10
is this right??
To find the x-intercepts of the function f(x) = 15x^2 - 12x - 48, we need to determine the values of x for which f(x) is equal to zero.
To do this, we can set f(x) equal to zero:
15x^2 - 12x - 48 = 0
Now, we have a quadratic equation in the form of ax^2 + bx + c = 0, where a = 15, b = -12, and c = -48.
To solve this quadratic equation, we can use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
Plugging in the values, we get:
x = (-(-12) ± √((-12)^2 - 4(15)(-48))) / (2(15))
Simplifying further:
x = (12 ± √(144 + 2880)) / 30
x = (12 ± √3024) / 30
Now, let's simplify the expression under the square root:
√3024 = √(144 * 21) = √(12^2 * 21) = 12√21
Finally, we can rewrite the solutions for x:
x = (12 ± 12√21) / 30
Now, we can simplify this expression further by factoring out a common factor of 12 from the numerator:
x = 12(1 ± √21) / 30
This can be further simplified by dividing both the numerator and denominator by their common factor of 6:
x = 2(1 ± √21) / 5
So, the x-intercepts of the function f(x) = 15x^2 - 12x - 48 are given by the solutions:
x = 2(1 + √21) / 5 ≈ 3.26
and
x = 2(1 - √21) / 5 ≈ -1.26
Therefore, the x-intercepts of the function are approximately x ≈ 3.26 and x ≈ -1.26.