Posted by **Shreya** on Wednesday, January 4, 2012 at 8:34pm.

7/(x-2)(x+5)-8/(x+5)(x-3)

7(x-3)-8(x-2)/(x-2)(x+5)(x-3)

7x-21-8x+16/(x-2)(x+5)(x-3)

7x-8x give me -1x and -21+16 give me -5. for numerator but it have to be -1/(x-2)(x-3)

i not know how to do this please explain process my way not different way.

- math calculus -
**Reiny**, Wednesday, January 4, 2012 at 8:57pm
You have to use brackets to show that both

x-2 and x+5 are factors of the bottom, so ...

7/((x-2)(x+5)) - 8/((x+5)(x-3)

so the lowest common denominator is (x-2)(x+5)(x-3)

we get

[ 7(x-3) - 8(x-2) ] /[(x-2)(x+5)(x-3)]

= [7x - 21 - 8x + 16]/[(x-2)(x+5)(x-3)]

= (-x - 5)/[(x-2)(x+5)(x-3)]

= -1(x+5)/[(x-2)(x+5)(x-3)]

= -1/[(x-2)(x-3)]

- math calculus -
**Shreya**, Wednesday, January 4, 2012 at 9:11pm
= (-x - 5)/[(x-2)(x+5)(x-3)]

i understand how u do this part

= -1(x+5)/[(x-2)(x+5)(x-3)]

i not understand how you get numerator

- math calculus -
**Reiny**, Wednesday, January 4, 2012 at 9:19pm
I simply factored out a -1

- math calculus -
**Shreya**, Wednesday, January 4, 2012 at 9:29pm
sorry but that the only thing i dont understand how do u factor that out? could you please explains slowly

- math calculus -
**Reiny**, Wednesday, January 4, 2012 at 9:40pm
suppose you had

2x + 4

then it would be 2(x+2)

suppose you had

-2x - 4

then it would be -2(x+2)

suppose you had -x -5

then it would be -1(x+5)

in each case, expand my answer and see what you get.

- math calculus -
**Shreya**, Wednesday, January 4, 2012 at 10:06pm
thank you very much reiny for taking time to explain :) u took all confusion away :)

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