Posted by Shreya on Wednesday, January 4, 2012 at 8:34pm.
You have to use brackets to show that both
x-2 and x+5 are factors of the bottom, so ...
7/((x-2)(x+5)) - 8/((x+5)(x-3)
so the lowest common denominator is (x-2)(x+5)(x-3)
we get
[ 7(x-3) - 8(x-2) ] /[(x-2)(x+5)(x-3)]
= [7x - 21 - 8x + 16]/[(x-2)(x+5)(x-3)]
= (-x - 5)/[(x-2)(x+5)(x-3)]
= -1(x+5)/[(x-2)(x+5)(x-3)]
= -1/[(x-2)(x-3)]
= (-x - 5)/[(x-2)(x+5)(x-3)]
i understand how u do this part
= -1(x+5)/[(x-2)(x+5)(x-3)]
i not understand how you get numerator
I simply factored out a -1
sorry but that the only thing i dont understand how do u factor that out? could you please explains slowly
suppose you had
2x + 4
then it would be 2(x+2)
suppose you had
-2x - 4
then it would be -2(x+2)
suppose you had -x -5
then it would be -1(x+5)
in each case, expand my answer and see what you get.
thank you very much reiny for taking time to explain :) u took all confusion away :)
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