Posted by Anonymous on Wednesday, January 4, 2012 at 8:26pm.
let the x-axis be the ground and the y-axis the axis of symmetry
Make a sketch, your jump will be when x = 5
equation is y = ax^2 + 50
but (20,0) is the x-intercept , the other is (-20,0)
so 0 = a(20^2) + 50
400a = -50
a = -1/8
y = (-1/8)x^2 + 50
when x = 5
y = (1/8)(25) + 50 = 46.875 ft
max stretch is 46.875 ft, (it will "touch" the ground)
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