Wednesday

April 16, 2014

April 16, 2014

Posted by **Anonymous** on Wednesday, January 4, 2012 at 8:26pm.

A. Write an equation to model the shape of the arch.

- math -
**Reiny**, Wednesday, January 4, 2012 at 8:33pmlet the x-axis be the ground and the y-axis the axis of symmetry

Make a sketch, your jump will be when x = 5

equation is y = ax^2 + 50

but (20,0) is the x-intercept , the other is (-20,0)

so 0 = a(20^2) + 50

400a = -50

a = -1/8

y = (-1/8)x^2 + 50

when x = 5

y = (1/8)(25) + 50 = 46.875 ft

max stretch is 46.875 ft, (it will "touch" the ground)

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