Posted by LISA on Wednesday, January 4, 2012 at 7:12pm.
the sum of the squares pf two postive consecutive even integers is 41. Find the integers.
MATH PLEASE HELP - Ms. Sue, Wednesday, January 4, 2012 at 7:16pm
3 and 4
4 and 5
5 and 6
MATH PLEASE HELP - LISA, Wednesday, January 4, 2012 at 7:19pm
its 4 and 5
MATH PLEASE HELP - Ms. Sue, Wednesday, January 4, 2012 at 7:27pm
MATH PLEASE HELP - Reiny, Wednesday, January 4, 2012 at 8:17pm
the number are even
so let the first be x
then the second is x+2
x^2 + (x+2)^2 = 41
x^2 + x^2 + 4x + 4 = 41
2x^2 + 4x - 37 = 0
No integer solution
We could tell from the beginning that this problem has no solution
the square of any even integer is even
the sum of two even number is even, but 41 is odd, so NO WAY!
MATH PLEASE HELP -- Oopa~ - Ms. Sue, Wednesday, January 4, 2012 at 8:38pm
I misread the problem.
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