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Posted by **LISA** on Wednesday, January 4, 2012 at 7:12pm.

- MATH PLEASE HELP -
**Ms. Sue**, Wednesday, January 4, 2012 at 7:16pmIs it?

3 and 4

4 and 5

5 and 6

- MATH PLEASE HELP -
**LISA**, Wednesday, January 4, 2012 at 7:19pmits 4 and 5

- MATH PLEASE HELP -
**Ms. Sue**, Wednesday, January 4, 2012 at 7:27pmRight.

- MATH PLEASE HELP -
**Reiny**, Wednesday, January 4, 2012 at 8:17pmthe number are even

so let the first be x

then the second is x+2

x^2 + (x+2)^2 = 41

x^2 + x^2 + 4x + 4 = 41

2x^2 + 4x - 37 = 0

No integer solution

We could tell from the beginning that this problem has no solution

the square of any even integer is even

the sum of two even number is even, but 41 is odd, so NO WAY!

- MATH PLEASE HELP -- Oopa~ -
**Ms. Sue**, Wednesday, January 4, 2012 at 8:38pmI misread the problem.

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