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Posted by on Wednesday, January 4, 2012 at 7:12pm.

the sum of the squares pf two postive consecutive even integers is 41. Find the integers.

  • MATH PLEASE HELP - , Wednesday, January 4, 2012 at 7:16pm

    Is it?

    3 and 4
    4 and 5
    5 and 6

  • MATH PLEASE HELP - , Wednesday, January 4, 2012 at 7:19pm

    its 4 and 5

  • MATH PLEASE HELP - , Wednesday, January 4, 2012 at 7:27pm

    Right.

  • MATH PLEASE HELP - , Wednesday, January 4, 2012 at 8:17pm

    the number are even
    so let the first be x
    then the second is x+2

    x^2 + (x+2)^2 = 41
    x^2 + x^2 + 4x + 4 = 41
    2x^2 + 4x - 37 = 0

    No integer solution

    We could tell from the beginning that this problem has no solution
    the square of any even integer is even
    the sum of two even number is even, but 41 is odd, so NO WAY!

  • MATH PLEASE HELP -- Oopa~ - , Wednesday, January 4, 2012 at 8:38pm

    I misread the problem.

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