Posted by **LISA** on Wednesday, January 4, 2012 at 7:12pm.

the sum of the squares pf two postive consecutive even integers is 41. Find the integers.

- MATH PLEASE HELP -
**Ms. Sue**, Wednesday, January 4, 2012 at 7:16pm
Is it?

3 and 4

4 and 5

5 and 6

- MATH PLEASE HELP -
**LISA**, Wednesday, January 4, 2012 at 7:19pm
its 4 and 5

- MATH PLEASE HELP -
**Ms. Sue**, Wednesday, January 4, 2012 at 7:27pm
Right.

- MATH PLEASE HELP -
**Reiny**, Wednesday, January 4, 2012 at 8:17pm
the number are even

so let the first be x

then the second is x+2

x^2 + (x+2)^2 = 41

x^2 + x^2 + 4x + 4 = 41

2x^2 + 4x - 37 = 0

No integer solution

We could tell from the beginning that this problem has no solution

the square of any even integer is even

the sum of two even number is even, but 41 is odd, so NO WAY!

- MATH PLEASE HELP -- Oopa~ -
**Ms. Sue**, Wednesday, January 4, 2012 at 8:38pm
I misread the problem.

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