In parallelogram DEFG, DH = x + 1, HF = 3y, GH = 3x – 4, and HE = 5y + 1. Find the values of x and y.
The parallelogram has D at the top left E at the top right, G at the bottom left and and F at the bottom right with H in the middle.
Thank You ^0^
Since the diagonals bisect each other,
x+1 = 3y
3x-4 = 5y+1
x - 3y = -1
3x - 5y = 5
3x - 9y = -3
3x - 5y = 5
4y = 8
y=2
x=5
holy crap it's been a decade and we're still struggling on the same exact questions
bruh this is trash, no wonder brainy is better
BROO why is this question even a thingg, ITS BEEN A DECADE AND WE STILL HAVENT GOT IT LOLL
yes it does work
It adds up 5+1=6
3 x 2=6
3(5)-4=11
5(2)+1=11
So they are correct.