Posted by **Rebecca** on Wednesday, January 4, 2012 at 3:26pm.

At 9:00 on Saturday morning, two bicyclists heading in opposite directions pass each other on a bicycle path. The bicyclist heading north is riding 5 km/hour faster than the bicyclist heading south. At 10:30, they are 40.5 km apart. find both of their rates.

- 7th Grade Math -
**Steve**, Wednesday, January 4, 2012 at 4:22pm
Since they are heading north and south, let the southern speed be s, so the northern speed is s+5

After 1.5 hours, the distance is 40.5km

distance is speed * time

40.5 = (s + s+5) * 1.5

27 = 2s+5

22 = 2s

s = 11

so, the cyclist going south moves at 11km/hr, north at 16 km/hr

they are moving apart at 27km/hr, so at 1.5 hours they are 40.5 km apart.

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