Post a New Question

Physics

posted by on .

A 20 kg table initially at rest on a horizontal floor requires a 136 N horizontal force to set it in motion. Once the table is in motion, a 71 N horizontal force keeps it moving at a constant velocity. What is the coefficient of kinetic friction between the table and floor?

  • Physics - ,

    Wt = mg = 20 kg * 9.8 N/kg = 196 N. =
    Weight of table.

    Ft = 196 N. @ 0 Deg. = Force of table.
    Fp = 196*sin(0) = 0 = Force parallel to floor.
    Fv = 196*cos(0) = 196 N. = Force perpendicular to the floor.

    Fn = Fap-Fp-Fk = ma = 0, a = 0.
    71-0-Fk = 0,
    Fk = 71 N. = Force of kinetic friction.

    u*Fv = 71,
    196u = 71,
    u = 0.362 = Kinetic coefficient of friction.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question