A 62 kg water skier, moving at 14 m/s , lets go of the towline.
a.Find her momentum. 868kgm/s
b.What impulse is needed to bring her to rest? -868Ns
c.If the water exerts an average force of -275 N on the skier, how long must the force act? 3.16 s
d.How far does she travel during this time? ??
To find the distance traveled by the water skier during the time the force acts on her, we can use the equation:
d = v0 * t + (1/2) * a * t^2
where:
d is the distance traveled,
v0 is the initial velocity,
t is the time the force acts on the skier, and
a is the acceleration experienced by the skier.
In this case, we can assume the acceleration is constant since the force is exerted over a short period of time.
We can determine the acceleration using Newton's second law of motion:
F = m * a
where:
F is the force,
m is the mass, and
a is the acceleration.
Given that the force exerted by the water on the skier is -275 N (negative since it acts in the opposite direction of motion), and the mass of the skier is 62 kg, we can solve for the acceleration:
a = F / m = -275 N / 62 kg = -4.44 m/s^2
Now, we can substitute the values into the first equation:
d = (14 m/s) * t + (1/2) * (-4.44 m/s^2) * t^2
Simplifying the equation, we get:
d = 14t - 2.22t^2
To find the distance traveled, we need to know the exact time the force acts on the skier.