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September 18, 2014

September 18, 2014

Posted by **Jennifer** on Tuesday, January 3, 2012 at 11:32pm.

1. Represent the height as ‘x’ and then write the width in terms of x (for example, 2x, 5.5x, 0.5x, 0.3x).

2. Write down the formula for a rectangle’s area.

3. Substitute the values from step 1 and the original problem into the area formula.

What kind of equation do you need to solve in the end of step 3? How would you go about solving that equation? What other kinds of problems would lead you to this type of equation? Finally, what are the answers for the width and height?

Can you please explain step by step how you got the results? So I can best understand how to solve a similar problem? Thanks!

- algebra -
**Reiny**, Wednesday, January 4, 2012 at 12:08amI will follow the suggested steps even though I don't think they are the best approach.

(I will do it the better way after)

let the height be x

then the width = (1/2)x (it said it was half the height)

(1/2)(x)(x) = 50

times 2

x^2 = 100

x=√100 = 10

so the height is 10

and the width is (1/2)(10) = 5

other way: (notice no fractions)

let the width be x

then the height is 2x (notice the width is 1/2 the height)

2x^2 = 50

x^2 = 25

x = √25 = 5

so the width is 5 and the

height is 2x = 10

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