Sandy decided to give one-fourth of her CDs to Jenn. Then she gives one-half of the remaining CDs to Bob. If she is left with 6 CDs,how many CDs did she have to begin with?
Let X be the original number of CDs owned.
X - X/4 -(1/2)(3X/4) = 6
3X/4 -3X/8 = 3X/8 = 6
X = 16
Woah ^^ I'm confused. Please explaain
The answer was to Jessica.
Algebra was used.
To solve this problem, let's break it down step by step.
Step 1: Sandy gives one-fourth of her CDs to Jenn.
So, she is left with 3/4 of her original CDs.
Step 2: Sandy gives one-half of the remaining CDs to Bob.
This means she keeps 1/2 of 3/4 of her original CDs, which is (3/4) * (1/2) = 3/8 of her original CDs.
Step 3: Now we are told that she is left with 6 CDs.
We need to find out how many CDs she had initially.
To find the initial number of CDs, we'll set up an equation:
(3/8) * Initial CDs = 6
To isolate the initial CDs, we need to divide both sides of the equation by (3/8):
Initial CDs = 6 / (3/8)
To divide by a fraction, we'll multiply by its reciprocal:
Initial CDs = 6 * (8/3)
Simplifying the right side of the equation:
Initial CDs = 48 / 3
Initial CDs = 16
Therefore, Sandy initially had 16 CDs.