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November 24, 2014

November 24, 2014

Posted by **Jenn** on Tuesday, January 3, 2012 at 11:07pm.

f(x)=e^x

g(x)=log_x

h(x)=x/x+8

- Functions -
**drwls**, Wednesday, January 4, 2012 at 5:55amI am not sure what you mean by

g(x) = log_x

If your g(x) is log(base e)(x) = ln x,

then

f*g(x) = e^(lnx) = x

and

f*g*h(x) = h(x) = x/(x+8)

However, x/(x+8) must be positive for g(x) to be defined.

Therefore x> 0 or x < -8 is the domain

- Functions -
**Kon**, Wednesday, January 4, 2012 at 7:21ami thinkthe only ans is x> 0,its impossible to log a negative no.u may try to use a calculator to prove it. then x/x should be done first.so x < -8 or x> -8 is also possible.

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