Posted by **Jennifer** on Tuesday, January 3, 2012 at 8:11pm.

Solve the following equation in the complex number system

x^4+x^3+4x^2+10x-60=0

College Algebra - Reiny, Monday, January 2, 2012 at 11:49pm

hint

x = 2 and x = -3 are roots

so either do long division by x-2 and x+3

to get a quadratic or do it by synthetic division.

Solve that quadratic using the formula.

College Algebra - Jennifer, Tuesday, January 3, 2012 at 8:10pm

so what would my equation be to figure this question out?

- College Algebra -
**Damon**, Tuesday, January 3, 2012 at 8:28pm
Do what Reiny said, step by step

****__x^3__+3x^2__+10x__+30________

x-2 | x^4 + x^3 + 4 x^2 + 10 x - 60

******x^4 -2x^3

******----------------------------

**********3 x^3 + 4 x^2 + 10 x - 60

**********3 x^3 - 6 x^2

**********--------------------------

****************+10 x^2 + 10 x -60

****************+10 x^2 - 20 x

******************-----------------

*************************+30 x -60

*************************+30 x -60

*************************---------

Remainder = 0

Now divide x^3+3x^2+10x+30

by x + 3

That will leave you with a quadratic which you solve with the quadratic equation, probably resulting in two complex conjugate roots.

- College Algebra -
**Amanda**, Monday, September 17, 2012 at 4:38pm
Find X such that the point(x,9) is 10 units from (9,3)

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