Posted by Jennifer on Tuesday, January 3, 2012 at 8:11pm.
Do what Reiny said, step by step
****__x^3__+3x^2__+10x__+30________
x-2 | x^4 + x^3 + 4 x^2 + 10 x - 60
******x^4 -2x^3
******----------------------------
**********3 x^3 + 4 x^2 + 10 x - 60
**********3 x^3 - 6 x^2
**********--------------------------
****************+10 x^2 + 10 x -60
****************+10 x^2 - 20 x
******************-----------------
*************************+30 x -60
*************************+30 x -60
*************************---------
Remainder = 0
Now divide x^3+3x^2+10x+30
by x + 3
That will leave you with a quadratic which you solve with the quadratic equation, probably resulting in two complex conjugate roots.
Find X such that the point(x,9) is 10 units from (9,3)
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