ALGEBRA 1
posted by CRAig .
The height h is the time of seconds that the ball has been in the air with an initial vertical velocity of 48 feet per second from a height of 5 feet above the ground is given by the equation
h=16t^2 + 48t + 5
where t is the time in seconds that the ball has been in the air. After how many seconds in the ball at of 37 feet.

I have not seen a gravity problem in feet instead of meters for a while.
37 = 16 t^2 + 48 t + 5
16 t^2  48 t + 32 = 0
t^2  3 t + 2 = 0
(t2)(t1) = 0
t = 1 or 2
so
the ball is at 37 feet after one second on the way up and at two seconds on the way down