Posted by **Kendall** on Tuesday, January 3, 2012 at 6:17pm.

A deorbit burn has been performed. During this deorbit burn a pre-calculated Delta V (change in velocity) of 290 ft/s (or 88.4 m/s) will be used to decrease the Shuttle’s altitude from 205 miles to 60 miles at perigee. The Shuttle’s Orbital Maneuvering System (OMS) engines provide a combined thrust of 12,000 force-pounds or 53,000 Newtons. The Shuttle weighs 2.50 x 105 lbs when fully loaded. The Shuttle has a mass of 1.13 x 105 kg when fully loaded.

Calculate how long a de-orbit burn must last in minutes and seconds to achieve the Shuttle’s change in altitude from 205 miles to 60 miles at perigee.

- Physics -
**Eric**, Tuesday, February 5, 2013 at 12:07am
Method 1

Step 1: Solve for acceleration

From F=ma, rearrange to a=F/m

a=F/m= (53000 N)/(1.13 x 〖10〗^5 kg)= .469026549 〖m/s〗^2

Step 2: Solve for time

t=∆v/a=(88.4 m/s)/(.469026549 〖m/s〗^2 )=188.4754716 seconds

Step 3: Convert seconds to minutes

(188.4754716 seconds)/60=3.141257859 minutes

Step 4: Convert minutes to seconds

.141257859 × 60=8.47547154 seconds

Final answer:

It would require 3 minutes and 8 seconds of burn time to change the Shuttle’s altitude from 205 miles to 60 miles at perigee.

## Answer This Question

## Related Questions

- Physics - The De-orbit Burn The Shuttle must reduce its velocity at a pre-...
- physics - A de-orbit burn, similar to that presented in the previous math ...
- Physics, Math, Aerospace, Engineering - A de-orbit burn, similar (but not the ...
- Physics - The shuttle must perform the de-orbit burn to change its orbit so ...
- Physics - The shuttle must perform the de-orbit burn to change its orbit so ...
- Math - Calculate how long a de-orbit burn must last in minutes and seconds to ...
- 11th grade - Calculate the minimum change in velocity (delta V or ∆V) ...
- Math/Science - Calculate the minimum change in velocity (delta V or ∆V) ...
- Rocket Science - Calculate the minimum change in velocity (delta V or ∆V...
- physics - A test rocket is launched vertically from ground level (y = 0 m), at ...

More Related Questions