math
posted by Melissa on .
determine the 100th term of the arithmetic sequence with t7=465 and t13=219

t7=465 > a+6d=465
t13=219 > a+12d=219
subtract:
6d = 246
d = 41
in 1st equation: a+6(41) = 465
a = 711
term(100) = a+99d = ......
you finish it