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Boron forms a gaseous compound with hydrogen with empirical formula BH3. a 1.05L sample of this compound at a pressure of 88 mm Hg at 295K has a mass of .138g. what is the molecular formula of the compound?

  • chemistry - ,

    Use PV = nRT to solve for n = number of moles BH3, then n = grams/molar mass. You know n and grams, solve for molar mass.
    X*empirical formula mass = molar mass
    Solve for X and substitute into
    (BH3)x so the molecular formula will be BxH3x

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