Posted by mary on Tuesday, January 3, 2012 at 5:13am.
Use PV = nRT to solve for n = number of moles BH3, then n = grams/molar mass. You know n and grams, solve for molar mass.
X*empirical formula mass = molar mass
Solve for X and substitute into
(BH3)x so the molecular formula will be BxH3x
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