Posted by Jules on Monday, January 2, 2012 at 9:25pm.
An 89 N box of oranges is being pushed across a horizontal floor. As it moves, it is slowing at a constant rate of 1.20 m/s each second. The push force has a horizontal component of 25 N and a vertical component of 30 N downward. Calculate the coefficient of kinetic friction between the box and floor.

physics  Henry, Tuesday, January 3, 2012 at 11:02pm
Fb = 89 N. @ 0 deg. = Force of box.
Fp = 89*sin(0) = 0 = Force parallel to
the floor.
Fv = 89*cos(0) = 89 N. = Force perpendicular to the floor.
mg = 89,
m=89/g = 89/9.8 = 9.08 kg=Mass of box.
Fn = FapFpFk = ma,
250Fk = 9.08*1.2 = 10.9,
Fk = 10.925 = 35.9,
Fk = 35.9 N. = Force of kinetic friction.
u(89+30) = 35.9
119u = 35.9,
u = 0.30 = Coefficient of kinetic friction.
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