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January 30, 2015

January 30, 2015

Posted by **-Untamed-** on Monday, January 2, 2012 at 7:57pm.

I solved this out by multiplying the (a+1) by (a-1) and multiplying (a-1) with (a+1) To get (a+1)(a-1) as the denominator. Then I did the same with the numerators and got this:

1(a-1) + 1(a+1)/(a+1)(a-1)

And I got 2a/(a+1)(a-1)

But still sometimes this process confuses me so could someone please explain and solve this problem for me step by step so I actually understand it well? Thanks.

- Calculus -
**Damon**, Monday, January 2, 2012 at 8:42pm1/(a+1) + (1/a-1)

(a-1)/[(a+1)(a-1)] + (a+1)/[(a+1)(a-1)]

[ a-1+a+1 ] / [(a+1)(a-1)]

2a / (a^2-1)

so I agree with you

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