B is the midpoint of segment AC and D is the midpoint of segment CE. Solve for x, given BD=3x+5 and AE=4x+20.

Sorry I couldn't get the link for the picture but, the diagram is a picture of a triangle with a C at the top, and A and E on
the bottom angles, with segment BD going through the middle of the triangle.

Thank You ^0^

BD= 1/2 AE.

So the real equation is 6x+10=4x+20
isolate the variable and you will get your answer.
the answer is x=5

triangle BCD is similar to triangle ACE (side, angle C, side)

AC = 2 BC
therefore AE = 2 BD
therefore
4x+20 = 2 (3x+5) solve that

No, pickle is not right on all the answers.

AE is divided into two pairs of equal lengths. BD contains one of each pair.

So, BD is half the length of AE.

2(3x+5) = 4x+20
x = 5

x=5

Thank You So Much! ^0^

whats answer

What's the answer?

Is pickle right?

AE = 2(BD)

4x + 20 = 2(3x + 5)
4x + 20 = 6x + 10
20 = 2x +10
10 = 2x
5 = x