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September 16, 2014

September 16, 2014

Posted by **Jennifer** on Sunday, January 1, 2012 at 6:01pm.

- College Algebra -
**Steve**, Sunday, January 1, 2012 at 6:49pmwhat's the problem? Just plug and chug:

f(g) = ln(g-1) = ln(1+e^x-1) = ln(e^x) = x

g(f) = 1+e^f = 1 + e^(ln (x-1)) = 1 + x-1 = x

Just keep in mind the definition of a logarithm:

e^lnx = x

ln e^x = x

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