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December 19, 2014

December 19, 2014

Posted by **jasmin** on Thursday, December 29, 2011 at 3:29pm.

- algebra 2 -
**Reiny**, Thursday, December 29, 2011 at 4:33pmlet the width of the border be x inches

then

(10+2x)^2 - 100 ≤ 300

100 + 40x + 4x^2 - 100 - 300 ≤ 0

x^2+ 10x - 75 ≤ 0

(x+15)(x-5) ≤ 0

x = 5

So the largest frame is 20 by 20

check: Area of whole frame = 400

area of photo = 100

area of tiles = 300

- algebra 2 -
**Eric**, Thursday, December 29, 2011 at 4:34pmThe largest possible frame width is 17 inches long per side.

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