Friday

November 28, 2014

November 28, 2014

Posted by **arslan** on Thursday, December 29, 2011 at 12:09pm.

A 2D rigid body shown in the figure-2 has constant density ρ kg/m2. It is a thin circular disc of radius R centered at point P that contains a circular cavity centered at point Q. The distance PQ = R/3. Find the center of mass of the rigid body

- physics -
**drwls**, Thursday, December 29, 2011 at 7:53pmI can't see your Fig. 2, but all you have to do is subract the moment of inertia of cavity, treating it as if it were a mass with the same density. Subtract it from the moment of inertia of the larger disc, treating it as having no hole. You may have to use the parallel axis theorem for moments of inertia about axes that do not pass through a center of symmetry.

**Answer this Question**

**Related Questions**

Physics - Consider a torque ⃗τ that is constant in both magnitude and...

Science Maths - Sir, My question is as below:- Three particles a b & c of mass m...

Physics - Consider a torque ⃗τ that is constant in both magnitude and...

Physics - KE/Inertia - The rigid body shown in Figure 10-66 (it is a triangle ...

Physic (concepts-please check my thoughts) - A net torque applied to a rigid ...

physics (please check work) - Four identical particles, each with mass m, are ...

Physics - A round body of mass M, radius R, and moment of inertia I= BMR^2 is ...

Physics - A round body of mass M, radius R, and moment of inertia I= BMR^2 is ...

Physics - A round body of mass M, radius R, and moment of inertia I= BMR^2 is ...

physics - a body of mass 20 kg suspended from a rigid support is rotated on a ...