Posted by Watermelon on Thursday, December 29, 2011 at 12:56am.
a) 18000 * 1.05^5
b) 36000 = 18000 * 1.05^n
n = ln 2/ln 1.05
c) sum of first n terms of a GP is
a(1-r^n)/(1-r) = 18000(1-1.05^6)/(1-1.05)
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