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October 31, 2014

October 31, 2014

Posted by **April** on Wednesday, December 28, 2011 at 11:17pm.

right along a horizontal, frictionless surface by

a constant, horizontal force of 16.8 N.

Find the speed of the block after it has

moved 2.3 m.

Answer in units of m/s

- Physics -
**drwls**, Thursday, December 29, 2011 at 4:05amFirst compute the acceleration,

a = F/m = 2.044 m/s^2

V = s

- Physics -
**drwls**, Thursday, December 29, 2011 at 4:09amFirst compute the acceleration,

a = F/m = 2.044 m/s^2

Then use

V(final) = sqrt(2 a X)

where X is the distance travelled.

You could also use:

Work done on block = F*X

= final kinetic energy,

= (1/2)M Vfinal^2.

and then solve for Vfinal.

Vfinal = sqrt[2*(F/M)*x]

You will get the same result.

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