Sunday

January 25, 2015

January 25, 2015

Posted by **April** on Wednesday, December 28, 2011 at 11:17pm.

right along a horizontal, frictionless surface by

a constant, horizontal force of 16.8 N.

Find the speed of the block after it has

moved 2.3 m.

Answer in units of m/s

- Physics -
**drwls**, Thursday, December 29, 2011 at 4:05amFirst compute the acceleration,

a = F/m = 2.044 m/s^2

V = s

- Physics -
**drwls**, Thursday, December 29, 2011 at 4:09amFirst compute the acceleration,

a = F/m = 2.044 m/s^2

Then use

V(final) = sqrt(2 a X)

where X is the distance travelled.

You could also use:

Work done on block = F*X

= final kinetic energy,

= (1/2)M Vfinal^2.

and then solve for Vfinal.

Vfinal = sqrt[2*(F/M)*x]

You will get the same result.

**Answer this Question**

**Related Questions**

Physics - A 4.9 kg block initially at rest is pulled to the right along a ...

Physics - A 5.9 kg block initially at rest is pulled to the right along a ...

Physics - A 8.9 kg block initially at rest is pulled to the right along a ...

Physics - A 3.6 kg block initially at rest is pulled to the right along a ...

Physics - A 3.8 kg block initially at rest is pulled to the right along a ...

physics - A 3.2 kg block initially at rest is pulled to the right along a ...

physics - A 9 kg block initially at rest is pulled to the right along a ...

Physics - A 3.3 kg block initially at rest is pulled to the right along a ...

physics - 8) A 6.0-kg block initially at rest is pulled to the right along a ...

11th grade - A 7.8 kg block initially at rest is pulled to the right along a ...