Posted by **Lily** on Wednesday, December 28, 2011 at 8:36pm.

The perimeter of triangle ABC is 29 meters. Line segment AD bisects angle A. Find AB and AC. CD=5cm, DB=4 cm.(triangle angle bisector theorem)

- Geometry -
**Damon**, Wednesday, December 28, 2011 at 9:24pm
AB/AC = 4/5 so AB = 4 AC/5

AB + AC + 9 = 29

so

AB + AC = 20

4 AC/5 + AC = 20

4 AC + 5 AC = 100

9 AC = 100

etc

- Geometry -
**Anonymous**, Sunday, January 22, 2012 at 4:36pm
AC= 11.11111111

AB= 8.888888889

- Geometry -
**hey**, Tuesday, January 14, 2014 at 8:26am
You forgot to change 29m to 2900cm.

- Geometry -
**Anonymous**, Friday, February 20, 2015 at 12:34am
*The problem should say 29 cm.

AB/AC=4/5, so 4AC=5AB, which is also 4/5(AC)=AB.

AB+BC+AC=29

AB+AC+9=29

AB+AC=20

4/5(AC)+AC=20

9/5(AC)=20

AC=11 1/9

AB=20-AC

AB=20-11 1/9

AB=8 8/9

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