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Posted by on Wednesday, December 28, 2011 at 8:36pm.

The perimeter of triangle ABC is 29 meters. Line segment AD bisects angle A. Find AB and AC. CD=5cm, DB=4 cm.(triangle angle bisector theorem)

  • Geometry - , Wednesday, December 28, 2011 at 9:24pm

    AB/AC = 4/5 so AB = 4 AC/5

    AB + AC + 9 = 29
    so
    AB + AC = 20

    4 AC/5 + AC = 20
    4 AC + 5 AC = 100
    9 AC = 100
    etc

  • Geometry - , Sunday, January 22, 2012 at 4:36pm

    AC= 11.11111111
    AB= 8.888888889

  • Geometry - , Tuesday, January 14, 2014 at 8:26am

    You forgot to change 29m to 2900cm.

  • Geometry - , Friday, February 20, 2015 at 12:34am

    *The problem should say 29 cm.

    AB/AC=4/5, so 4AC=5AB, which is also 4/5(AC)=AB.

    AB+BC+AC=29
    AB+AC+9=29
    AB+AC=20
    4/5(AC)+AC=20
    9/5(AC)=20
    AC=11 1/9

    AB=20-AC
    AB=20-11 1/9
    AB=8 8/9

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