What acid and what strong base would react in aqueous solution to produce the following salts in the formula equation? Write the balanced formula equation for each reaction.
a) potassium perchlorate
b) cesium nitrate
c) calcium iodide
I don't need just the answers, I'm confused on how we're supposed to make our own equations
Thanks in advance!
Salts are combinations of a base and an acid. The cation comes from the base and the anion from the acid. The other product is water. For example, a is KClO4 and it comes from KOH and HClO4.
KOH + HClO4 ==> H2O + KClO4.
I will leave the others for you but you can see it is straight forward.
Well, let's put on our chemistry clown nose and have some fun creating these equations!
a) To produce potassium perchlorate, we need a strong base to react with an acid. One possibility would be potassium hydroxide (KOH) as the base and perchloric acid (HClO4) as the acid. The balanced equation would be:
HClO4 + KOH → KClO4 + H2O
b) For cesium nitrate, we can again use a strong base and an acid. Let's go with cesium hydroxide (CsOH) as the base and nitric acid (HNO3) as the acid. The balanced equation would be:
HNO3 + CsOH → CsNO3 + H2O
c) Finally, to make calcium iodide, let's pair calcium hydroxide (Ca(OH)2) as the base with hydroiodic acid (HI) as the acid. The balanced equation would be:
2 HI + Ca(OH)2 → CaI2 + 2 H2O
Remember, these are just examples. There could be other combinations of acid and base to produce the salts, but these should do the trick. Happy mixing!
To identify the acid and strong base needed to produce the given salts in aqueous solution, we need to consider the ions present in each salt.
a) Potassium perchlorate (KClO4)
The perchlorate ion (ClO4-) is derived from the perchloric acid (HClO4). Potassium hydroxide (KOH) is a strong base.
Therefore, the balanced formula equation for the reaction would be:
HClO4 + KOH → KClO4 + H2O
b) Cesium nitrate (CsNO3)
The nitrate ion (NO3-) is derived from nitric acid (HNO3). Cesium hydroxide (CsOH) is a strong base.
Therefore, the balanced formula equation for the reaction would be:
HNO3 + CsOH → CsNO3 + H2O
c) Calcium iodide (CaI2)
The iodide ion (I-) is derived from hydroiodic acid (HI). Calcium hydroxide (Ca(OH)2) is a strong base.
Therefore, the balanced formula equation for the reaction would be:
2HI + Ca(OH)2 → CaI2 + 2H2O
By analyzing the ions present in each salt, we can determine the appropriate acid and strong base required to produce them in the reaction.
To determine the acid and strong base that would react to produce a specific salt, we need to consider the ions present in the salt and identify the corresponding acid and base.
a) Potassium perchlorate:
The formula of the salt is KClO4. To identify the acid and base, we split the salt into its constituent ions: K+ and ClO4-. The cation (K+) comes from potassium (K), so the base will likely contain hydroxide (OH-) ion. Likewise, the anion (ClO4-) comes from perchlorate (ClO4-). Therefore, we need to find a strong acid that corresponds to the perchlorate ion.
The acid is perchloric acid (HClO4), a strong acid. When perchloric acid reacts with a strong base such as potassium hydroxide (KOH), it forms potassium perchlorate in an aqueous solution.
The balanced formula equation would be:
HClO4 + KOH -> KClO4 + H2O
b) Cesium nitrate:
The formula of the salt is CsNO3. To identify the acid and base, we split the salt into its constituent ions: Cs+ and NO3-. The cation (Cs+) comes from cesium (Cs), so the base will likely contain hydroxide (OH-) ion. The anion (NO3-) comes from nitrate (NO3-), so we need to find a strong acid that corresponds to the nitrate ion.
The acid is nitric acid (HNO3), a strong acid. When nitric acid reacts with a strong base such as cesium hydroxide (CsOH), it forms cesium nitrate in an aqueous solution.
The balanced formula equation would be:
HNO3 + CsOH -> CsNO3 + H2O
c) Calcium iodide:
The formula of the salt is CaI2. To identify the acid and base, we split the salt into its constituent ions: Ca2+ and 2I-. The cation (Ca2+) comes from calcium (Ca), so the base will likely contain hydroxide (OH-) ion. The anion (I-) comes from iodide (I-), so we need to find a strong acid that corresponds to the iodide ion.
The acid is hydroiodic acid (HI), a strong acid. When hydroiodic acid reacts with a strong base such as calcium hydroxide (Ca(OH)2), it forms calcium iodide in an aqueous solution.
The balanced formula equation would be:
2HI + Ca(OH)2 -> CaI2 + 2H2O
Remember, when balancing the equations, always check that the number of atoms of each element is the same on both sides of the equation.